15a^2-58a+48=0

Solution for 15a^2-58a+48=0 equation:

15a^2-58a+48=0

a = 15; b = -58; c = +48;
Δ = b2-4ac
Δ = -582-4·15·48
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-58)-22}{2*15}=\frac{36}{30}
=1+1/5
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-58)+22}{2*15}=\frac{80}{30}
=2+2/3
$